1. Use Maple to make a plot (on an appropriate timescale) of [A], [B], and [C] versus time (all 3 on the same axes) for the irreversible reaction A + B -> C with k = 7 x 106 and initial conditions [A]=1, [B]=0.35,[C]=0. 2. Show that there is only one physically meaningful (i.e. non-negative) solution of the equilibrium condition given at the bottom of p3 of Text 3A for the reversible reaction A + B <-> C. 3. EXTRA CREDIT. Sometimes chemical kineticists will write a reaction as
3 A -> B (1).
But in reality there aren't any reactions that require simultaneous collisions of 3 molecules the way this appears to imply. The more likely reality is that there is an intermediate, say X, and what really happens is
2 A <-> X, and A + X -> B. (2)
Under what circumstances would the simpler scheme (1) give approximately the same dynamical predictions as the more honest scheme (2)?4. For the Schlogl model with k=1, use Maple to make a quantitatively accurate picture of (an appropriate portion of) the region in the ab parameter plane where multiple equilibria coexist. How to do it: (i) Write down the equilibrium (steady-state) condition. (ii) Observe that this is a cubic in x, and that varying b just shifts the cubic vertically. Therefore, for (a,k) values for which the cubic has extrema, b can be adjusted to obtain multiple equilibria (intersections of the cubic with the x-axis). By differentiating the cubic with respect to x, and using the quadratic formula, find what the extreme points are (values of x), and a condition on a and k which says when the cubic does have extrema. (iii) Find the values of b that correspond to the two extreme points. These depend on a and k. With k=1, we can plot these values of b versus a. Use the "view=[]" plot option to exclude any portions of the curves that have b<0. To give you something to compare with, here's my plot:
The region with multiple steady states is the lower right.